The length of a rectangle is 5 meters more than its width. The perimeter is 66 meters. Find the length and the width of the rectangle

L = w+5

2 L + 2 w = 66 or L + w = 33
so
w + 5 + w = 33
2 w = 28
w = 14 etc

P = 2L + 2W

66 = 2(w + 5) + 2W

66 = 4W + 10

56 = 4W

14 = W

Well, let's solve this mystery! Let's call the width "x" meters. According to the information given, the length is 5 meters more than the width, so the length would be "x + 5" meters.

To find the perimeter of a rectangle, we add up all the sides. In this case, we have two sides of width "x" and two sides of length "x + 5". So, the perimeter is:

2(x) + 2(x + 5)

Equating this to 66 meters, we can solve for x:

2x + 2(x + 5) = 66

2x + 2x + 10 = 66

4x + 10 = 66

4x = 56

x = 14

So, the width of the rectangle is 14 meters. Since the length is 5 meters more than the width, the length would be 14 + 5 = 19 meters.

Therefore, the length of the rectangle is 19 meters and the width is 14 meters.

To find the length and width of the rectangle, we need to set up an equation based on the given information. Let's start solving the problem step by step:

Let's assume that the width of the rectangle is "w" meters.
Since the length is 5 meters more than the width, we can represent the length as "w + 5" meters.

The perimeter of a rectangle is given by the formula: P = 2(length + width).
In our case, the perimeter is 66 meters, so we can write the equation as:
66 = 2(w + w + 5)

Simplifying this equation, we get:
66 = 2(2w + 5)
66 = 4w + 10
56 = 4w
w = 14

Now that we have the width, we can find the length by substituting the value of "w" into our expression for the length:
Length = w + 5 = 14 + 5 = 19

Therefore, the width of the rectangle is 14 meters, and the length is 19 meters.