a spaceship is moving at 1000 m/s release a satellite of mass 1000 kg at a speed of 10 000 m/s. what is the mass of the spaceship if it slows down to a velocity of 910 m/s?

v₁ =910 m/s

m₂=1000 kg
v₂=10000 m/s
u= 1000 m/s
m₁=?
(m₁+m₂)u = m₁v₁ +m₂v₂
m₁=m₂(v₂-u)/(u-v₁)=
=1000(10000-1000)/(1000-910) = 100000 kg

989

A spaceship moving at 1000 m/s releases a satellite of mass

1000 kg at a speed of 10 000m/s. What is the mass of the
spaceship if it slows down to a velocity of 910 m/s?
answer=91kg

100000kg

Efg

I don't know

111.2

91kg

The correct answer is 91 kg. Here's how to solve it:

Let's call the mass of the spaceship "m". According to conservation of momentum, the total momentum of the spaceship-satellite system before and after the satellite is released must be the same. We can use this fact to solve for "m".

Before the satellite is released, the momentum of the spaceship-satellite system is:

p1 = m * v1

where v1 = 1000 m/s is the velocity of the spaceship before the satellite is released.

After the satellite is released, the momentum of the spaceship-satellite system is:

p2 = m * v2 + m2 * v2'

where v2 = 910 m/s is the final velocity of the spaceship (after it has slowed down), v2' = 10,000 m/s is the velocity of the satellite relative to the spaceship, and m2 = 1000 kg is the mass of the satellite.

Since momentum is conserved, we have:

p1 = p2

or

m * v1 = m * v2 + m2 * v2'

Solving for "m", we get:

m = m2 * (v2' - v1) / (v1 - v2)

Plugging in the given values, we get:

m = 1000 kg * (10,000 m/s - 1000 m/s) / (1000 m/s - 910 m/s) = 91 kg

Therefore, the mass of the spaceship is 91 kg.

To solve this problem, we can use the principle of conservation of momentum.

The conservation of momentum states that the total momentum of an isolated system remains constant if no external forces are acting on it.

Let's assume the initial momentum of the spaceship and the satellite is P1 and the combined mass of the spaceship and the satellite is M1. After releasing the satellite, the momentum of the spaceship and satellite system will be conserved.

The initial momentum of the spaceship and the satellite system is given by:

P1 = (mass of the spaceship) × (velocity of the spaceship) + (mass of the satellite) × (velocity of the satellite)

P1 = M1 * 1000 m/s + 1000 kg * 10,000 m/s

Now, let's assume the final momentum of the spaceship and the satellite system after the spaceship slows down is P2. Since momentum is conserved, P2 should be equal to P1.

P2 = (mass of the spaceship) × (final velocity of the spaceship) + (mass of the satellite) × (velocity of the satellite)

P2 = M2 * 910 m/s + 1000 kg * 10,000 m/s

Since P1 = P2, we can equate the two expressions:

M1 * 1000 m/s + 1000 kg * 10,000 m/s = M2 * 910 m/s + 1000 kg * 10,000 m/s

Now, we can solve for M2, which represents the mass of the spaceship after it slows down to a velocity of 910 m/s.

M2 * 910 m/s = M1 * 1000 m/s

M2 = (M1 * 1000 m/s) / 910 m/s

M2 = M1 * 1.0989

Therefore, the mass of the spaceship after it slows down to a velocity of 910 m/s is approximately 1.0989 times the initial mass of the spaceship.