An object with a mass of 5 kg moves at a constant velocity when it is pulled by a horizontal force of 5 N on a level surface. What is the acceleration of the object if the object is pulled with a force of 25 N?

Assuming friction is not velocity dependent, the the friction is 5N.

if one pulls with 25N
net force=m*a
25-5=5 a solve for a

0.50

To determine the acceleration of an object, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

The formula for calculating acceleration is:

acceleration = net force / mass

In this case, the mass of the object is given as 5 kg.

To find the net force when the object is pulled with a force of 25 N, we need to subtract the force required to maintain the constant velocity from the applied force.

Given that the force required to maintain constant velocity is 5 N, the net force can be calculated as:

net force = applied force - force required to maintain constant velocity

net force = 25 N - 5 N
net force = 20 N

Now, we can substitute the values into the formula to find the acceleration:

acceleration = net force / mass
acceleration = 20 N / 5 kg
acceleration = 4 m/s^2

Therefore, the acceleration of the object when pulled with a force of 25 N is 4 m/s^2.