How many moles of hydrochloric acid are required to react with 2.57 moles of calcium hydroxide in a neutralization reaction?
In a neutralization reaction between hydrochloric acid (HCl) and calcium hydroxide (Ca(OH)2), the balanced chemical equation is:
2HCl + Ca(OH)2 → CaCl2 + 2H2O
According to the equation, it takes 2 moles of hydrochloric acid to react with 1 mole of calcium hydroxide.
Given that we have 2.57 moles of calcium hydroxide, we can set up a proportion to determine the number of moles of hydrochloric acid needed:
2 moles HCl / 1 mole Ca(OH)2 = x moles HCl / 2.57 moles Ca(OH)2
Using cross multiplication:
2 moles HCl × 2.57 moles Ca(OH)2 = 1 mole Ca(OH)2 × x moles HCl
5.14 moles HCl = x moles HCl
Therefore, you would need 5.14 moles of hydrochloric acid to react with 2.57 moles of calcium hydroxide in the neutralization reaction.
To find out how many moles of hydrochloric acid are required to react with 2.57 moles of calcium hydroxide, we need to determine their stoichiometry.
First, let's write the balanced chemical equation for the neutralization reaction between hydrochloric acid (HCl) and calcium hydroxide (Ca(OH)2):
2HCl + Ca(OH)2 -> CaCl2 + 2H2O
From the balanced equation, we can see that 2 moles of hydrochloric acid react with 1 mole of calcium hydroxide.
So, if we have 2.57 moles of calcium hydroxide, we can use the stoichiometry to determine the number of moles of hydrochloric acid required:
2HCl : 1Ca(OH)2
x moles : 2.57 moles
To solve for x, we can set up a simple proportion:
2HCl / 1Ca(OH)2 = x moles / 2.57 moles
Cross-multiplying, we get:
2HCl * 2.57 moles = x moles * 1Ca(OH)2
Simplifying the equation, we find:
x = (2HCl * 2.57 moles) / 1Ca(OH)2
x = 5.14 moles
Therefore, 5.14 moles of hydrochloric acid are required to react with 2.57 moles of calcium hydroxide in the neutralization reaction.