physics
posted by Sami .
Three identical uniform meter sticks are placed on the floor. The first stick lies along the y axis from y = 0.320 m to y = 1.32 m. The second stick lies along the x axis from x = 0.330 m to x = 1.33 m. The third stick is positioned so that one end is on the x axis at x = 0.640 m, and the other end is on the y axis at y = 0.768 m. Calculate the location of the center of mass of the meter sticks.

since all the sticks are the same size and mass, the center is just the average of all the (x,y) midpoints:
(0,(.32+1.32)/2)
((.33+1.33)/2,0)
(.64/2,.768/2)
so, the center of mass is at
((0+(.33+1.33)/2+.64/2)/3,((.32+1.32)/2+0+.768/2)/3)
= (0.383,0.401)