Calculate the tension in a horizontal string that whirls a 1.9-kg toy in a circle of radius 2.3m when it moves at 2.8m/s on an icy surface.
Express your answer to two significant figures and include the appropriate units.
1.9(2.8)^2 .. then divid by 2.3
I got 12.30 N , is this correct ?
T=ma=mv²/R=1.9•2.8²/2.3= 6.48 N
To calculate the tension in the string, you can use the centripetal force equation:
F = (m*v^2) / r,
where:
F is the centripetal force,
m is the mass of the toy (1.9 kg),
v is the velocity of the toy (2.8 m/s),
and r is the radius of the circular path (2.3 m).
Substituting the given values into the equation:
F = (1.9 kg * (2.8 m/s)^2) / 2.3 m.
Plugging the numbers into the calculator, we get:
F = (1.9 * (2.8)^2) / 2.3 = 12.326086956521739.
Rounding the final answer to two significant figures, the tension in the string is approximately 12 N.
So, yes, your answer of 12.30 N is correct. The appropriate unit for tension is Newtons (N).
To calculate the tension in the horizontal string, we can use the centripetal force equation:
Tension = (mass x velocity^2) / radius
Plugging in the given values:
mass = 1.9 kg, velocity = 2.8 m/s, and radius = 2.3 m
Tension = (1.9 kg x (2.8 m/s)^2) / 2.3 m
Calculating this equation:
Tension = (1.9 kg x 7.84 m^2/s^2) / 2.3 m
Tension = 6.704 kg·m/s^2 / 2.3 m
Tension ≈ 2.92 N
Therefore, the tension in the horizontal string, when it moves at 2.8 m/s on an icy surface with a radius of 2.3 m, is approximately 2.92 N (newtons).