A 10-ohm resistor is attached to a 20-ohm resistor in series. This combination is then attached to a 30-ohm resistor in parallel. This is then connected to a 120-V battery. What is the current drawn from the battery?
you have two 30 ohms in parallel, total effective resistance 15 ohms, in a 120 battery (wow), current=120/15 amps
A 10-ohm resistor is attached to a 20-ohm resistor in series. This combination is then attached to a 30-ohm resistor in parallel. This is then connected to a 6-V battery. What is the current drawn from the battery?
To find the current drawn from the battery, we can use Ohm's Law, which states that the current (I) flowing through a resistor is equal to the voltage (V) across the resistor divided by the resistance (R) of the resistor.
First, let's calculate the total resistance (RT) of the combination of resistors in series:
RT = 10 Ω + 20 Ω = 30 Ω
Next, let's calculate the equivalent resistance (RP) of the resistors in parallel. For resistors in parallel, the equivalent resistance is given by the reciprocal of the sum of the reciprocals of the individual resistances:
1/RP = 1/30 Ω + 1/30 Ω + 1/30 Ω
1/RP = 3/30 Ω
1/RP = 1/10 Ω
RP = 10 Ω
Now, we can calculate the total resistance (RTotal) of the circuit. For resistors in series and parallel combinations, we sum the resistances:
RTotal = RP + RT = 10 Ω + 30 Ω = 40 Ω
Using Ohm's Law, we can now find the current (I):
I = V / RTotal
I = 120 V / 40 Ω
I = 3 A
Therefore, the current drawn from the battery is 3 Amperes.