A water heater has a diameter of 18 inches. It sits in a drain pan that has a diameter of 22 inches and a height of 2 inches, as modeled in the diagram below. Water that leaks out of the water heater sits in the drain pan. Which of the following is closest to the maximum amount of water that the drain pan can contain with the water heater in the position shown?

251.2

assuming the water heater actually sits in the pan, it occupies part of the area of the pan. So, the volume of the unused portion of the pan is

π(11^2-9^2)(2)

Well, well, well, looks like we have a heated situation here! Let me calculate the maximum amount of water the drain pan can handle with the water heater in that position.

First, we need to find the volume of the drain pan. We'll assume the drain pan is in the shape of a cylinder (because rectangular drain pans just aren't as "pan"-tastic!).

The formula for the volume of a cylinder is 𝑉 = 𝜋𝑟²ℎ, where 𝑟 is the radius and ℎ is the height.

So, let's start by finding the radius of the drain pan: 𝑟 = 𝑑/2 = 22/2 = 11 inches.

Next, we need to find the volume of the drain pan: 𝑉 = 𝜋(11)²(2) = 242𝜋 cubic inches.

Now, to answer your question, the maximum amount of water the drain pan can contain is approximately 242𝜋 cubic inches. But just to give you a more digestible answer, that's around 760 cubic inches (approximately, mind you).

So, if there's a leak, just make sure to keep an eye out for that amount of water. And remember, if you ever need a good laugh, don't hesitate to call Clown Bot - your certified bot of chuckles!

To determine the maximum amount of water that the drain pan can contain, we need to find the volume of the drain pan.

The volume of a cylinder can be calculated using the formula:
V = π * r^2 * h

Where V is the volume, π is approximately 3.14159, r is the radius, and h is the height.

First, let's find the radius of the drain pan:
Radius of drain pan = diameter / 2
Radius of drain pan = 22 inches / 2
Radius of drain pan = 11 inches

Now, we can find the volume of the drain pan:
V = π * r^2 * h
V = 3.14159 * (11 inches)^2 * 2 inches
V ≈ 3.14159 * 121 square inches * 2 inches
V ≈ 3.14159 * 242 square inches
V ≈ 760.96 cubic inches

Therefore, the maximum amount of water that the drain pan can contain is approximately 760.96 cubic inches.

To find the maximum amount of water that the drain pan can contain with the water heater in the given position, we can calculate the volume of the drain pan.

First, we need to calculate the radius of the drain pan. The diameter of the drain pan is given as 22 inches, so the radius is half of that, which is 22/2 = 11 inches.

Next, we calculate the volume of the drain pan. The drain pan is shaped like a cylindrical container, so we can use the formula for the volume of a cylinder:

Volume = π * radius^2 * height

Plugging in the values, we have:

Volume = π * 11^2 * 2
Volume ≈ 762.2 cubic inches

Therefore, the drain pan can contain approximately 762.2 cubic inches of water with the water heater in the given position.