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When 100mL of 0.60mol per liter K3BO3 is added to 200 mL of 0.40 mol per liter Ca3(BO3)2 Find

a)moles of K3BO
b) moles of Ca(BO3)2
c)final concentration of K+
d)final concentration of Ca+2
e) final concentration of BO3 negative 3

  • Chem -

    I'm assuming Ca3(BO3)2 has no Ksp. I couldn't find one.
    a. mols = M x L = ?
    b. mols = M x L = ?
    c. mols K = 3 x mols K3BO3 and (K^+) = mols K/total L
    d. mol BO3^3- from K3BO3 = mols K3BO3
    mols BO3^3- from Ca3(BO3)2 = 2 x mols Ca3(NO3)2.
    Then (BO3^3-) = total mols BO3^3-/total L

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