posted by BILL on .
When 100mL of 0.60mol per liter K3BO3 is added to 200 mL of 0.40 mol per liter Ca3(BO3)2 Find
a)moles of K3BO
b) moles of Ca(BO3)2
c)final concentration of K+
d)final concentration of Ca+2
e) final concentration of BO3 negative 3
I'm assuming Ca3(BO3)2 has no Ksp. I couldn't find one.
a. mols = M x L = ?
b. mols = M x L = ?
c. mols K = 3 x mols K3BO3 and (K^+) = mols K/total L
d. mol BO3^3- from K3BO3 = mols K3BO3
mols BO3^3- from Ca3(BO3)2 = 2 x mols Ca3(NO3)2.
Then (BO3^3-) = total mols BO3^3-/total L