Posted by jnky on Tuesday, March 18, 2014 at 11:39pm.
x^2cosx2xsinx2cosx

derivatives  Reiny, Wednesday, March 19, 2014 at 12:00am
I assume that you want the derivative, since you titles your post that way.
if y = x^2cosx2xsinx2cosx
dy/dx = (x^2)(sinx) + 2x cosx  2x(cosx)  2sinx + 2sinx
= x^2( sinx) + 4x( cosx)
etc if needed

derivatives  oops  Steve, Wednesday, March 19, 2014 at 5:53am
d/dx sinx = cosx

derivatives  Reiny, Wednesday, March 19, 2014 at 7:36am
yup!
sloppiness on my part
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