Posted by **Anonymous** on Tuesday, March 18, 2014 at 9:29pm.

What are the axes of symmetry in the graphs of the equations -2x^2 and -2x^2 + 4? I think the vertices are (0,0) and (0,4).

- Math -
**Reiny**, Tuesday, March 18, 2014 at 9:52pm
You talk about equations, but show no equation.

You must have meant the equations to be

y = -2x^2 and y = -2x^2 + 4

You are asking for the axes of symmetry but instead state the vertices.

You were correct that the vertices are (0,0) and (0,4) respectively.

so the axes of symmetry are x = 0 for both of them,

that is, the axis of symmetry is the y-axis

- Math -
**Anonymous**, Tuesday, March 18, 2014 at 10:02pm
Thank you. Yes, I meant to put the y in there. Are the x-intercepts 0 and 4, respectively?

- Math -
**Anonymous**, Tuesday, March 18, 2014 at 10:04pm
I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that.

- Math -
**Reiny**, Tuesday, March 18, 2014 at 10:37pm
yes , the x-intercepts are 0 and 4, respectively

confused about your second reply, the vertices are indeed (0,0) and (0,4)

<<I mean 0 for -2x^2. Sorry about the 4, I didn't mean to put that. >> , don't even know what that is supposed to say.

see,

http://www.wolframalpha.com/input/?i=y+%3D+-2x%5E2+%2C+y+%3D+-2x%5E2+%2B+4

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