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March 26, 2017

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The Ksp of tin(II) hydroxide, Sn(OH)2, is 5.45 × 10-27. Calculate the solubility of this compound in g/L.

  • Chemistry - ,

    ............Sn(OH)2 ==> Sn^2+ + 2OH^-
    I............solid.......0........0
    C............solid.......x........2x
    E............solid.......x........2x

    Ksp = (Sn^2+)(OH^-)^2
    5.45E-27 = (x)(2x)^2
    Solve for x = solubility in mols/L.
    Then grams = mols x molar mass

  • Chemistry - ,

    thank you

  • Chemistry - ,

    1.695*10^-7

  • Chemistry - ,

    heather is incorrect

  • Chemistry - ,

    how is heather incorrect?

  • Chemistry - ,

    Heather is correct

  • Chemistry - ,

    Heather is correct. Atta girl Heather. You da real mvp

  • Chemistry - ,

    Heather sucks.

  • Chemistry - ,

    The answer is 1.10861×10^-9 in sapling. Heather truly does suck.

  • Chemistry - ,

    Poor Heather she was only trying. LOL!

  • Chemistry - ,

    Heather is correct, even on sapling. thank you heather, nicely done on the math. the rest of you who say she isn't need to check yourselves

  • Chemistry - ,

    the correct answer is 1.10861*10^-9 on sapling.
    Heather sucks.

  • Chemistry - ,

    heather is right

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