# Chemistry

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The Ksp of tin(II) hydroxide, Sn(OH)2, is 5.45 × 10-27. Calculate the solubility of this compound in g/L.

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............Sn(OH)2 ==> Sn^2+ + 2OH^-
I............solid.......0........0
C............solid.......x........2x
E............solid.......x........2x

Ksp = (Sn^2+)(OH^-)^2
5.45E-27 = (x)(2x)^2
Solve for x = solubility in mols/L.
Then grams = mols x molar mass

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thank you

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1.695*10^-7

• Chemistry - ,

heather is incorrect

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how is heather incorrect?

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Heather is correct

• Chemistry - ,

Heather is correct. Atta girl Heather. You da real mvp

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Heather sucks.

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The answer is 1.10861×10^-9 in sapling. Heather truly does suck.

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Poor Heather she was only trying. LOL!

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Heather is correct, even on sapling. thank you heather, nicely done on the math. the rest of you who say she isn't need to check yourselves

• Chemistry - ,

the correct answer is 1.10861*10^-9 on sapling.
Heather sucks.

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heather is right

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heather is right

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heather played u, its 1.108*10^-9

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