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PHYSICS

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A 5.00-kg box slides 7.00 m across the floor before coming to rest. What is the coefficient of kinetic friction between the floor and the box if the box had an initial speed of 3.00 m/s?

  • PHYSICS - ,

    Initial speed = 3 m/s
    acceleration constant during braking
    therefore average speed during stop = 3/2 = 1.5 m/s
    time to stop = t =7 m / 1.5 m/s = 4.67 seconds
    v = Vi +a t
    0 = 3 + a(4.67)
    a = -0.643 m/s^2

    F = m a
    F = 5 (.643)
    F = 3.21 Newtons

    F = mu (weight)
    3.21 = mu (5)(9.81)
    mu = - .0655

  • PHYSICS - ,

    thank you.

  • PHYSICS - ,

    You are welcome. As always, check my arithmetic.

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