Posted by **Bethany** on Tuesday, March 18, 2014 at 2:26am.

Two ships left the same port at the same time. One travelled at 16kn/h on a course of 275 degrees while the other at 20 km/h of 225 degrees. How far apart are the ships after a. 2 hours? b. 4 hours?

*note: this is a trigonometry question using the cosine law.

Thanks!

- Math -
**Damon**, Tuesday, March 18, 2014 at 3:39am
275 - 225 = 50 degrees difference in heading

In two hours

Ship A went 16 * 2 = 32

Sbip B went 20 * 2 = 40

c^2 = a^2 + b^2 - 2 a b cos C

c^2 = (32)^2 + (40)^2 -2(32)(40)cos 50

c^2 = 1024 + 1600 - 1646.5

c^2 = 978.4

c = 31.3

For pert B, similar triangle, double time, double distance

= 62.6

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