Posted by Bethany on Tuesday, March 18, 2014 at 2:26am.
Two ships left the same port at the same time. One travelled at 16kn/h on a course of 275 degrees while the other at 20 km/h of 225 degrees. How far apart are the ships after a. 2 hours? b. 4 hours?
*note: this is a trigonometry question using the cosine law.
Thanks!

Math  Damon, Tuesday, March 18, 2014 at 3:39am
275  225 = 50 degrees difference in heading
In two hours
Ship A went 16 * 2 = 32
Sbip B went 20 * 2 = 40
c^2 = a^2 + b^2  2 a b cos C
c^2 = (32)^2 + (40)^2 2(32)(40)cos 50
c^2 = 1024 + 1600  1646.5
c^2 = 978.4
c = 31.3
For pert B, similar triangle, double time, double distance
= 62.6
Answer This Question
Related Questions
 trig  Help! Ships A and B leave port at the same time and sail on straight ...
 Geometry  Two ships leave San Francisco at the same time. One travles 40 ...
 math  2 boats left the harbour at the same time. One travelled at 10km/h on a ...
 math  could someone show me how to write this or set up this equation?2 ships ...
 math  an observer in a lighthouse 300 ft above sea level observes 2 ships ...
 trig  Two ships, one sailing at 30 km/hr and the other at 45 km/hr, left port ...
 Pre Calc!  Two ships, one sailing at 30 km/hr and the other at 45 km/hr, left ...
 geometry  Two ships leave a harbor at the same time, traveling on courses that ...
 10th grade  Two ships leave a harbor at the same time, traveling on courses ...
 geometry  the pilot of a plane flying 2000 meters above sea level observes two ...
More Related Questions