Posted by **Maho** on Monday, March 17, 2014 at 11:39pm.

Using a table of standard electrode potentials (as in Appendix M of your text), calculate the standard cell potential, Eo, for: 2 Fe2+(aq) + Cl2(g) 2 Fe3+(aq) + 2 Cl(aq).

Answer:

Anode: 2 Fe2+ 2 Fe3+ + 2 e

Eox = 0.771 V

Cathode: Cl2 + 2 e 2 Cl Ered = +1.36 V

Enet = +0.59 V

- Chemistry Check Please!!! -
**DrBob222**, Tuesday, March 18, 2014 at 12:14am
I think Eox = -0.771 and

Ered = +1.36

Then 1.36 + (-0.771) = ?

Your answer is right; I don't agree with what you called Eox. The anode is oxidized, yes, and that is an oxidation, yes. But the potential for that electrode is -0.771. The reduction potential is 0.771; the oxidn potential is -0.771.

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