posted by Ann on .
Dissolving solid CaCl2 H2O in a large volume of water is endothermic to the extent of 14.6 kj/mol. Also given: CaCl2(s)+6H2O(l)->CaCl2* 6H2O(s) delta H = -97.0 kj what is the heat of solution of anhydrous CaCl2 in a large volume of water?
Is that a typo first line. Perhaps should be CaCl2.6H2O. If so just add the two equations to obtain
CaCl2(s) ==> CaCl2(aq) about -82 kJ/mol but that isn't exact.