Upon decomposition, one sample of magnesium fluoride produced 1.95 kg of magnesium and 3.05 kg of fluorine. A second sample produced 1.10 kg of magnesium.
There must be a question in here somewhere.
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To find the amount of fluorine produced in the second sample, we can use the information from the first sample as a reference.
The molar mass of magnesium (Mg) is 24.31 g/mol, and the molar mass of fluorine (F) is 18.998 g/mol.
Let's calculate the moles of magnesium and fluorine in the first sample:
Moles of magnesium = mass of magnesium / molar mass of magnesium
Moles of magnesium = 1.95 kg * 1000 g/kg / 24.31 g/mol
Moles of fluorine = mass of fluorine / molar mass of fluorine
Moles of fluorine = 3.05 kg * 1000 g/kg / 18.998 g/mol
The ratio of moles of magnesium to fluorine in magnesium fluoride is 1:2. Therefore, the moles of fluorine should be twice the moles of magnesium.
Let's calculate the moles of magnesium and fluorine in the second sample:
Moles of magnesium in the second sample = mass of magnesium in the second sample / molar mass of magnesium
Moles of magnesium in the second sample = 1.10 kg * 1000 g/kg / 24.31 g/mol
Since the ratio of moles of magnesium to fluorine is 1:2, we can use this ratio to calculate the moles of fluorine in the second sample:
Moles of fluorine in the second sample = Moles of magnesium in the second sample * 2
Finally, to find the mass of fluorine in the second sample, we multiply the moles of fluorine by the molar mass of fluorine:
Mass of fluorine in the second sample = Moles of fluorine in the second sample * molar mass of fluorine
By following these calculations, we can determine the amount of fluorine produced in the second sample.
To determine the mass of fluorine produced in the second sample, we need to use the information from the first sample as a reference.
First, we need to find the ratio between the masses of magnesium and fluorine in the first sample. From the given information, we know that 1.95 kg of magnesium produced 3.05 kg of fluorine.
Ratio of magnesium to fluorine in the first sample:
Mass of magnesium / Mass of fluorine = 1.95 kg / 3.05 kg
Next, we can use this ratio to find the mass of fluorine produced in the second sample using the given mass of magnesium.
Mass of fluorine in the second sample:
Mass of magnesium in second sample × (Mass of fluorine in first sample / Mass of magnesium in first sample)
Substituting the values into the formula:
Mass of fluorine in the second sample = 1.10 kg × (3.05 kg / 1.95 kg)
Calculating this expression:
Mass of fluorine in the second sample = 1.10 kg × 1.56
Therefore, the mass of fluorine produced in the second sample is approximately 1.71 kg.