Tuesday

July 29, 2014

July 29, 2014

Posted by **Sandy** on Sunday, March 16, 2014 at 6:40pm.

y'' - 2y' + y = 0 , y(2) = 0 , y'(2) = 1

- Calculus -
**Steve**, Sunday, March 16, 2014 at 11:33pmy = e^x (c1 + c2*x)

y' = e^x (c1 + c2 + c2*x)

Now plug in the initial conditions to get

e^2 (c1 + 2c2) = 0

e^2 (c1 + c2 + 2c2) = 1

Now just solve for c1 and c2

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