Calculus
posted by Sandy on .
Solve the initialvalue problem.
y''  2y' + y = 0 , y(2) = 0 , y'(2) = 1

y = e^x (c1 + c2*x)
y' = e^x (c1 + c2 + c2*x)
Now plug in the initial conditions to get
e^2 (c1 + 2c2) = 0
e^2 (c1 + c2 + 2c2) = 1
Now just solve for c1 and c2