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March 4, 2015

March 4, 2015

Posted by **Anon** on Sunday, March 16, 2014 at 6:13pm.

- AP Calculus -
**Steve**, Monday, March 17, 2014 at 12:00ameach cross-section has base 2x and altitude x√3

So, we want to add up all those triangles

v = ∫[a,3] 1/2 * 2x * x√3 dy

= √3 ∫[a,3] x^2 dy

But,

y = |x| + a

y-a |x|

(y-a)^2 = x^2

v = √3 ∫[a,3] (y-a)^2 dy

and now it's cake, right?

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