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What is the molarity of an aqueous solution that is 6.44% glucose (C6H12O6) by mass? (Assume a density of 1.03 g/mL for the solution.)

  • Chemistry - ,

    6.44% by mass means 6.44 g glucose/100 g solution. What is the volume of the solution? That is mass = volume x density. You know d and you know mass; solve for volume in mL and convert to L.
    Then find mols solute. That is 6.44g/molar mass glucose.
    Finally, M = mols/L solution. You know mols and L solution.

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