Sunday

March 1, 2015

March 1, 2015

Posted by **Josh** on Sunday, March 16, 2014 at 3:54pm.

1) y^2 = x^2+a^2

2) y^2+ay = x^2+ax+a^2

- Calculus Help Please!!! -
**Damon**, Sunday, March 16, 2014 at 4:02pm2 y dy/dx = 2 x + 2 a da/dx

y dy/dx = (x+a da/dx)

dy/dx = (x + a da/dx)/y

or

dy/dx = (x + a da/dx)/(x^2+a^2)^.5

---------------------------------

2 y dy/dx + a dy/dx + y da/dx = 2 x^2 + a + x da/dx + 2 a da/dx

(2y+a)dy/dx = 2 x^2 +a +(x-y+2a)da/dx

dy/dx = [2 x^2 +a +(x-y+2a)da/dx]/(2y+a)

- Calculus Help Please!!! -
**bobpursley**, Sunday, March 16, 2014 at 4:58pmI suspect in each, a is a constant, so da/dx=0

- Calculus Help Please!!! -
**Damon**, Sunday, March 16, 2014 at 5:38pmI figured the same but he said specifically that a was variable.

- Calculus Help Please!!! -
**Josh**, Sunday, March 16, 2014 at 6:01pmMy answers were like these

1)

2yy'=2x+2a

y'=2x+2a/2y

2)

2yy'+ay'+y=2x+a+x+2a-y

2yy'+ay'=3x+3a-y

y'(2y+a)=3x+3a-y

y'=3x+3a-y/2y+a

And my teacher said I made mistakes with my answers but I couldn't figure out.

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