2 NaOH + CuSO4 Na2SO4 + Cu(OH)2
100g of Cu(OH)2 is needed. Assuming 100% yield, how much of 1M NaOH and 0.5M CuSO4 must be used in mL?
How many mols Cu(OH)2 do you need? That's mols = g/molar mass = 100/97.56 = approx 1 mol but you need to do it more accurately.
Convert mols Cu(OH)2 to mols NaOH = twice that = about 2 mol (again, do it more accurately).
M NaOH = mols/L. You know mols NaOH and M NaOH, solve for L NaOH and convert to mL.
Do the same to convert mols Cu(OH)2 to mols CuSO4 then M = mols/L. Finally, convert L CuSO4 to mL.
To determine the amount of 1M NaOH and 0.5M CuSO4 needed to obtain 100g of Cu(OH)2, you will need to calculate the required mole ratios based on the balanced chemical equation and use the concept of stoichiometry.
Let's start by calculating the molar mass of Cu(OH)2:
Cu(OH)2: Cu = 63.55 g/mol, O = 16.00 g/mol, H = 1.01 g/mol
Molar mass of Cu(OH)2 = 63.55 + 2(1.01) + 2(16.00) = 97.55 g/mol
Next, let's find the number of moles of Cu(OH)2 needed:
Number of moles = mass / molar mass
Number of moles = 100g / 97.55 g/mol ≈ 1.025 moles
Now, let's determine the mole ratio between Cu(OH)2 and NaOH using the balanced chemical equation:
2 NaOH + CuSO4 → Na2SO4 + Cu(OH)2
From the equation, we can see that the mole ratio between Cu(OH)2 and NaOH is 1:2.
Therefore, for 1 mole of Cu(OH)2, we need 2 moles of NaOH.
Since the concentration of NaOH is given as 1M, we can calculate the volume required using the formula:
Volume (in L) = moles / concentration
Volume (in L) = 2 moles / 1 M = 2 L
Finally, convert the volume from liters to milliliters:
Volume (in mL) = 2 L * 1000 mL/L = 2000 mL
So, you will need 2000 mL (or 2 liters) of 1M NaOH solution.
Moving on to CuSO4, let's determine the mole ratio between Cu(OH)2 and CuSO4 from the balanced chemical equation:
2 NaOH + CuSO4 → Na2SO4 + Cu(OH)2
From the equation, we can see that the mole ratio between Cu(OH)2 and CuSO4 is also 1:1.
Therefore, for 1 mole of Cu(OH)2, we need 1 mole of CuSO4.
Since the concentration of CuSO4 is given as 0.5M, we can calculate the volume required using the formula:
Volume (in L) = moles / concentration
Volume (in L) = 1 mole / 0.5 M = 2 L
Finally, convert the volume from liters to milliliters:
Volume (in mL) = 2 L * 1000 mL/L = 2000 mL
So, you will need 2000 mL (or 2 liters) of 0.5M CuSO4 solution.
In summary, to obtain 100g of Cu(OH)2 with 100% yield, you will need 2000 mL (or 2 liters) of 1M NaOH solution and 2000 mL (or 2 liters) of 0.5M CuSO4 solution.