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March 3, 2015

March 3, 2015

Posted by **marks** on Sunday, March 16, 2014 at 2:30pm.

- calculus -
**Steve**, Sunday, March 16, 2014 at 4:52pmfor shells, we need to integrate on y, since the area is rotated about a horizontal line, and the shells have thickness dy

v = ∫[1,2] 2πrh dy

where r = y-1 and h = x = ln y

v = 2π∫[1,2] (y-1)lny dy

Just use integration by parts to evaluate it.

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