You are pouring water from a cylindrical can is 7 cm in diameter and 10 cm high into a rectangular pan that is 20 cm in width, 9 cm in length and 14 cm deep. How many cans, can you pour into the pan? Use 22/7 for pi.
can vol = pi r^2 (10) = (22/7)(3.5)^2(10)
= 385 cm^3
pan vol = 20*9*14 = 2520 cm^3
2520/385 = six and a half
To find out how many cans of water can be poured into the pan, we need to calculate the volume of both the can and the pan.
First, let's calculate the volume of the cylindrical can using the formula for the volume of a cylinder:
Volume of the can = π * r^2 * h,
where π is the mathematical constant "pi", r is the radius, and h is the height.
Given that the diameter of the can is 7 cm, the radius can be calculated by dividing the diameter by 2:
radius of the can = 7 cm / 2 = 3.5 cm.
Now, let's calculate the volume of the can using the given height:
Volume of the can = π * (3.5 cm)^2 * 10 cm.
Since the value of π is given as 22/7, the calculation becomes:
Volume of the can = 22/7 * (3.5 cm)^2 * 10 cm.
Next, let's calculate the volume of the rectangular pan:
Volume of the pan = length * width * depth.
Given dimensions: length = 9 cm, width = 20 cm, depth = 14 cm.
Volume of the pan = 9 cm * 20 cm * 14 cm.
Now we have the volumes of both the can and the pan, so we can calculate how many cans can be poured into the pan.
Number of cans that can be poured into the pan = (Volume of the pan) / (Volume of one can).
I'm assuming that you want the answer as a whole number (no fractions or decimal places). However, keep in mind that in a real-life scenario, there might be some space left over in the pan.
Let's perform the calculations: