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March 4, 2015

March 4, 2015

Posted by **Scholastica** on Sunday, March 16, 2014 at 1:04pm.

x>0,y>0

- math -
**Bosnian**, Sunday, March 16, 2014 at 1:52pmsqrt ( 3 x * y ^ 3 )* sqrt ( 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =

sqrt ( 3 x * y ^ 3 * 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =

sqrt ( 6 x ^ 3 y ^ 4 ) / sqrt ( 6 x ^ 3 y ^ 4 ) = 1

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