Posted by Scholastica on .
Simplify,root 3xy^3 root 2x^2y divided by root 6x^3y^4
x>0,y>0

math 
Bosnian,
sqrt ( 3 x * y ^ 3 )* sqrt ( 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =
sqrt ( 3 x * y ^ 3 * 2 x ^ 2 * y ) / sqrt ( 6 x ^ 3 * y ^ 4 ) =
sqrt ( 6 x ^ 3 y ^ 4 ) / sqrt ( 6 x ^ 3 y ^ 4 ) = 1