Posted by **Stacey** on Saturday, March 15, 2014 at 11:16pm.

The acceleration of a particle moving only on a horizontal xy plane is given by a=5ti+6tj, where a is in meters per second-squared and t is in seconds. At t=0, the position vector r=(19.0m)i+(39.0m)j locates the particle, which then has the velocity vector v=(5.70m/s)i+(3.40m/s)j.At t=3.60s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?

For a) I got the answer -4.11 m/s. (This is correct)

I am having trouble finding b) though.

- Physics -
**Anonymous**, Saturday, September 12, 2015 at 10:24pm
not correct

## Answer This Question

## Related Questions

- Physics - The acceleration of a particle moving only on a horizontal xy plane is...
- Physics - The acceleration of a particle moving only on a horizontal xy plane is...
- physics - The acceleration of a particle moving only on a horizontal plane is ...
- physics - The acceleration of a particle moving only on a horizontal plane is ...
- Physics - A particle moved along the x axis with a constant acceleration of -85....
- physics - The position vector r of a particle moving in the xy plane is r=2ti+...
- Calculus - The position of a particle moving on a horizontal line is given by s(...
- Physics - A particle starts from the origin with velocity 2i m/s at t = 0 and ...
- Physics-can anyone check my work? - A particle starts from the origin with ...
- Physics - The position vector r of a particle moving in an xy plane is given by...

More Related Questions