Saturday

August 30, 2014

August 30, 2014

Posted by **tony** on Saturday, March 15, 2014 at 9:46pm.

Find the maximum value of f(x,y)=4xy, where x>0 and y>0, subject to the constraint (x^(2)/3^(2)+(y^(2)/4^(2)=1.

- cal -
**Steve**, Sunday, March 16, 2014 at 12:22pmf(3/√2 , 2√2) = 24

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