Algebra Question~!
posted by Gabby on .
The area of a rectangular room is given by the trinomial x^2+7x30. What are the possible dimensions of the rectangle? Use factoring. (1 point)

(x+10)(x3)

x^2 + 7x  30
= (x+10)(x3)
so the sides could be (x+10) and (x3) , were x > 3
or
x^2 + 7x  30
= (x2)(x+9  12/(x2) )
so the sides could be x2 and x+9  12/(x2)
or
x^2 + 7x  30
= (x+5)((x+2  40/(x+5) )
so the sides could be x+5 and x+2  40/(x+5)
or ...
as you can see there is no unique solution, I could pick any binomial for a first side, do a division and get the 2nd side.
Illustrate with numbers
Suppose you have an area of 30
so the sides could be 5 and 6
or
the sides could be 3 and 10
or
the sides could be 1 and 30
or
4.5 and 6 2/3
etc, can you see my point?