A 60 kg of sprinter accelerates from rest at 2.5 m?s^2 East for 4s. What force is acting and what is the final speed?
F = m*a = 60 * 2.5 = 150 N.
V = Vo + a*t = 0 + 2.5*4 = 10 m/s.
To find the force acting on the sprinter, we can use Newton's second law, which states that force is equal to mass multiplied by acceleration (F=ma). In this case, the mass of the sprinter is 60 kg and the acceleration is 2.5 m/s².
So, the force acting on the sprinter can be calculated as:
F = m * a
F = 60 kg * 2.5 m/s²
F = 150 N
Therefore, the force acting on the sprinter is 150 Newtons (N) to the East.
To find the final speed of the sprinter, we can use the formula v = u + at, where v is the final velocity, u is the initial velocity (which is 0 m/s since the sprinter starts from rest), a is the acceleration, and t is the time.
Given:
u = 0 m/s (initial velocity)
a = 2.5 m/s² (acceleration)
t = 4 s (time)
Using the formula v = u + at:
v = 0 m/s + (2.5 m/s² * 4 s)
v = 0 m/s + 10 m/s
v = 10 m/s
Therefore, the final speed of the sprinter after 4 seconds is 10 m/s.