How many grams of bromine are in 1.57 grams of phosphorus tribromide?
PBr3 is 271 grams per Mol
Br is 80 g /mol so Br3 is 240 g/mol
(240/271)1.57 = 1.39 grams
To calculate the number of grams of bromine in phosphorus tribromide, we need to determine the molar mass of phosphorus tribromide (PBr3).
The molar mass of phosphorus (P) is approximately 30.974 grams/mol, and the molar mass of bromine (Br) is approximately 79.904 grams/mol.
Since phosphorus tribromide contains one phosphorus atom and three bromine atoms, we can calculate its molar mass as follows:
Molar mass of PBr3 = (mass of P) + (3 * mass of Br)
= (30.974 grams/mol) + (3 * 79.904 grams/mol)
= 270.686 grams/mol
Now, we can use this molar mass to calculate the number of moles of phosphorus tribromide in 1.57 grams:
Number of moles = (mass given) / (molar mass)
= 1.57 grams / 270.686 grams/mol
≈ 0.0058 moles
Since there are three moles of bromine per one mole of phosphorus tribromide, we can calculate the number of moles of bromine in 0.0058 moles of phosphorus tribromide:
Number of moles of bromine = (3 * number of moles of phosphorus tribromide)
= (3 * 0.0058 moles)
= 0.0174 moles
Finally, we can calculate the mass of bromine in 0.0174 moles using its molar mass:
Mass = (number of moles) × (molar mass)
= 0.0174 moles × 79.904 grams/mol
≈ 1.39 grams
Therefore, there are approximately 1.39 grams of bromine in 1.57 grams of phosphorus tribromide.
To determine the number of grams of bromine in phosphorus tribromide (PBr3), we need to know the molar mass of bromine and phosphorus tribromide.
The molar mass of bromine (Br) is 79.9 grams per mole.
Phosphorus tribromide (PBr3) consists of one phosphorus atom (P) and three bromine atoms (Br). To calculate its molar mass, you multiply the molar mass of phosphorus (31 grams per mole) by 1, and the molar mass of bromine (79.9 grams per mole) by 3, then add them up:
Molar mass of PBr3 = (Molar mass of P) + 3*(Molar mass of Br)
= 31 + 3*(79.9)
= 31 + 239.7
= 270.7 grams per mole
Now that we know the molar mass of phosphorus tribromide (270.7 grams per mole), we can calculate the amount of bromine in 1.57 grams of PBr3 using the following equation:
Mass of bromine = (Mass of PBr3 / Molar mass of PBr3) * (Number of bromine atoms / Total number of atoms in PBr3) * Molar mass of bromine
Mass of bromine = (1.57 / 270.7) * (3 / 4) * 79.9
= 0.0058 * 0.75 * 79.9
≈ 0.347 grams
Therefore, there are approximately 0.347 grams of bromine in 1.57 grams of phosphorus tribromide.