Posted by **Stacey** on Friday, March 14, 2014 at 3:43pm.

The acceleration of a particle moving only on a horizontal xy plane is given by a=5ti+6tj, where a is in meters per second-squared and t is in seconds. At t=0, the position vector r=(19.0m)i+(39.0m)j locates the particle, which then has the velocity vector v=(5.70m/s)i+(3.40m/s)j.At t=3.60s, what are (a) its position vector in unit-vector notation and (b) the angle between its direction of travel and the positive direction of the x axis?

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**Stacey**, Friday, March 14, 2014 at 5:03pm
For a) I got the answer -4.11 m/s. (This is correct)

I am having trouble finding b) though.

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**Stacey**, Friday, March 14, 2014 at 5:04pm
I apologize, I meant this for my other question. I got 22.5 for this, but it was wrong. If someone can at least show calculations in getting this, I would appreciate it.

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