A number from 20 to 30 is drawn at random.
P(not a 23)
I think 1/11
probability that it IS 23 is 1/11
probability that it is NOT is 10/11
Hmmm. of the 11 numbers, how many are NOT 23?
To find the probability of not drawing a specific number (in this case, not drawing a 23) from a given range, we need to calculate the number of favorable outcomes (not drawing a 23) divided by the total number of possible outcomes (numbers from 20 to 30).
Total number of possible outcomes = 30 - 20 + 1 = 11 (since we include both 20 and 30)
The number of favorable outcomes is simply the number of numbers in the range from 20 to 30, excluding 23, which is 10 (i.e., {20, 21, 22, 24, 25, 26, 27, 28, 29, 30}).
So, the probability of not drawing a 23 is:
P(not a 23) = Number of favorable outcomes / Total number of possible outcomes
P(not a 23) = 10 / 11
Therefore, the probability of not drawing a 23 is 10/11, not 1/11 as you suggested.