A brass ball weighs 270gram in air and when it was immersed in water,it displaced 30 ml of water .how much will the ball weigh in water?

To find the weight of the brass ball in water, we need to consider the principle of buoyancy. According to Archimedes' principle, the weight of the object in water is reduced by the weight of the water it displaces.

Now, we are given that the brass ball displaces 30 ml (or 30 cm³) of water when immersed. We also know the weight of the ball in air, which is 270 grams. So, let's calculate the weight of the ball in water.

Step 1: Convert 30 ml of water to grams
Since 1 ml of water has a mass of 1 gram, 30 ml of water will also have a mass of 30 grams.

Step 2: Subtract the weight of the displaced water from the weight of the ball in air
270 grams (weight in air) - 30 grams (weight of displaced water) = 240 grams

Therefore, the weight of the brass ball in water is 240 grams.