Calculate the pH of a solution in which
a. [H3O+] = 7.8 x 10-7 M
b. [H3O+] = 5.1 x 10-6 M
c. [H3O+] = 6.1 x 10-5 M
d. [H3O+] = 9.3 x 10-4 M
See your post above.
a. Well, aren't you a perfectly balanced solution! With a [H3O+] of 7.8 x 10-7 M, your pH is gonna be pretty basic. I mean, who needs acidity when you can be basic and fabulous, right? So, get ready to shine with a pH of 6.11!
b. Alrighty then, we've got a [H3O+] of 5.1 x 10-6 M here. Looks like you're leaning towards the acidic side of life. It's like you're the vinegar to life's baking soda, ready to fizz up the pH scale. Brace yourself for a pH of 5.29!
c. Ahoy there, matey! With a [H3O+] of 6.1 x 10-5 M, you're sailing through the pH scale with a slight acidity. Not too harsh, just a gentle touch of sourness. Your pH treasure awaits you at 4.21!
d. Oh, we've got a over here with a [H3O+] of 9.3 x 10-4 M! You're like the acidity champion, ready to conquer the pH scale with your high concentration of hydrogen ions. Buckle up, because you're in for a wild ride with a pH of 3.03! Watch out for that burning sensation!
To calculate the pH of a solution, we can use the equation:
pH = -log[H3O+]
a. Given [H3O+] = 7.8 x 10^-7 M:
pH = -log(7.8 x 10^-7)
= -(-6.11)
= 6.11
Therefore, the pH of the solution is 6.11.
b. Given [H3O+] = 5.1 x 10^-6 M:
pH = -log(5.1 x 10^-6)
= -(-5.29)
= 5.29
Therefore, the pH of the solution is 5.29.
c. Given [H3O+] = 6.1 x 10^-5 M:
pH = -log(6.1 x 10^-5)
= -(-4.21)
= 4.21
Therefore, the pH of the solution is 4.21.
d. Given [H3O+] = 9.3 x 10^-4 M:
pH = -log(9.3 x 10^-4)
= -(-3.03)
= 3.03
Therefore, the pH of the solution is 3.03.
To calculate the pH of a solution, you can use the formula:
pH = -log[H3O+]
a. [H3O+] = 7.8 x 10-7 M
Using the formula, calculate the pH:
pH = -log(7.8 x 10-7)
= -log(7.8) - log(10-7)
Using the properties of logarithms, we know that log(10-7) can be simplified to -7:
pH = -log(7.8) - (-7)
= -log(7.8) + 7
≈ 6.11
b. [H3O+] = 5.1 x 10-6 M
Using the formula, calculate the pH:
pH = -log(5.1 x 10-6)
= -log(5.1) - log(10-6)
Using the properties of logarithms, we know that log(10-6) can be simplified to -6:
pH = -log(5.1) - (-6)
= -log(5.1) + 6
≈ 5.29
c. [H3O+] = 6.1 x 10-5 M
Using the formula, calculate the pH:
pH = -log(6.1 x 10-5)
= -log(6.1) - log(10-5)
Using the properties of logarithms, we know that log(10-5) can be simplified to -5:
pH = -log(6.1) - (-5)
= -log(6.1) + 5
≈ 4.21
d. [H3O+] = 9.3 x 10-4 M
Using the formula, calculate the pH:
pH = -log(9.3 x 10-4)
= -log(9.3) - log(10-4)
Using the properties of logarithms, we know that log(10-4) can be simplified to -4:
pH = -log(9.3) - (-4)
= -log(9.3) + 4
≈ 3.03
Therefore, the pH values are:
a. pH ≈ 6.11
b. pH ≈ 5.29
c. pH ≈ 4.21
d. pH ≈ 3.03