Monday
August 3, 2015

Homework Help: Algebra

Posted by Student on Tuesday, March 11, 2014 at 2:29pm.

1. √(9y - 196) + √196 = √49

My work:

I squared all 3 roots and got

9y - 196 + 196 = 49

The - 196 + 196 cancels out and we are left with 9y = 49.
divide 49 by 9. = 49/9. I'm pretty sure this is wrong. Can you show me where I messed up?

2. √x(√9 - 4/3) = √25

I'm not quite sure where to start with this.

3. (4 - 3√2)^2

My work: Distributive property gives me 4^2 - 3^2√2^2
The √2^2 simplifies to 2, 4^2 is 16, 3^2 is 9, So we have 16-9x2 Multiply first, so 16 - 18 = -2.

Is this correct?

4. √(135*b^2*c^3*d) * √(5b^2*d

Okay, so I broke this down like this: √135 * √b^2 * √c^2 * √c * √d * √5 * √b^2 * √d

Both the √b^2's and the √c^2 simplify down to b,b, and c

so now we have b^2c√(135 * 5cd^2) Simplifies to b^2cd√(5^2 * 3^2 * 3) which simplifies to 15b^2cd√3

Is this correct? If not can you tell me where I went wrong?

Thank you!

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Members