If a+b = c you cannot say that a^2+b^2 = c^2
√(9y - 196) + √196 = √49
√(9y - 196) + 14 = 7
√(9y - 196) = -7
But, √N is positive. So, you cannot have √(9y - 196) = -7
√x(√9 - 4/3) = √25
√x(3 - 4/3) = 5
√x(5/3) = 5
√x = 3
x = 9
(4 - 3√2)^2
recall that (a-b)^2 = a^2-2ab+b^2, so we have
16 - 24√2 + 18
44 - 24√2
almost right - you lost a √c
√(135*b^2*c^3*d) * √(5b^2*d)
√(135*5) √(b^2*b^2) √c^3 √(d*d)
15√3 b^2 c√c d
I have a couple questions about # 1.
Why can't it be a^2 + B^2 = c^2?
I think that's what I'm taught in class. Also, if you square everything, isn't still going to come out the same? If you do something to the entire expression, it doesn't change the value, right? If your conclusion is correct, what would I put for that answer? "No solution"? "No real solution"?
On #3. Would I do 44-24 = 20√2.. or?
For #1: When I get √(9y - 196) = -7 can I square each side to get 9y - 196 = 49? Then I can add 196 to both sides. It cancels out on the left side and I have 9y = 245. Then I can divide both sides by 9. I would get y = 27.2. Would that be correct?
You say that I can't use a^2 + b^2 = c^2, but that formula is called the Pythagorean theorem. I was instructed to use that formula. Am I misunderstanding what you're saying?
Answer this Question
HARD MATH PROBLEM (NEED HELP) - One day a person went to a hourse racing area,...
Physics - What force is needed to give a 0.25-kg arrow an acceleration of 196 m/...
Math is this right? - 5/28 divided by 1/7 = ? 5 Do I flip the second fraction ...
Math- CAN SOMEONE PLEASE CHECK MY WORK? - 7x+5y=-26 x=28-6y solve using ...
physics - A pendulum that consists of a 2kg mass swings a maximum vertical ...
Geometry - An isosceles right triangle has an area of 98cm squared. Find the ...
math i neeeeeeed help anyone - One day, a person went to horse racing area, ...
Math - A tunnel under a river is 196.8 ft below the surface at its lower point. ...
Math - Find an equation of the line that bisects the obtuse angles formed by the...
lcm - find the least common mutlipe of 420 196 Break down each number into prime...