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December 18, 2014

December 18, 2014

Posted by **Student** on Tuesday, March 11, 2014 at 11:24am.

1. 2√3 - √12

My answer: 2√3 - 2√3 = 0

2. √(5p + 5)^2 = √(6p + )^2

I got the answer p = 4

3. √(28) + √(63) + √(175)

This one seems so simple. I tried multiple times, but I can't seem to get the correct answer. I think i'm making some little mistake in the calculations or something.

4. √(2w + 5) + 4 = √(25)

My answer: -3.5

5. √(18)/√(8 - 3)

My answer: -12 - 9 √2

- Algebra -
**Steve**, Tuesday, March 11, 2014 at 11:50am#1 ok

#2 ok if you meant √(6p+1)

#3

√28 + √63 + √175

2√7 + 3√7 + 5√7 = 10√7

#4

√(2w+5) + 4 = √25

√(2w+5) = 1

2w+5 = 1

2w = -4

w = -2

#5

√18/√(8-3)

3√2 / √5

(3√10)/5

If you meant

√18/(√8-3)

(3√2)(√8+3)/5

(12+9√2)/5

How did you come up with your answer?

- Algebra -
**Student**, Tuesday, March 11, 2014 at 12:11pmI have a question.

#3: On my calculator, √28 + √63 + √175 = 6.06, but 10√7 = 26.5. Shouldn't they = the same number?

As for #5.. I'm not really sure, tbh. I tried that problem a while a go and I'm not quite sure where I was going with it.

- Algebra -
**Steve**, Tuesday, March 11, 2014 at 12:25pmThere's no way that

√28 + √63 + √175 = 6.06

You must have hit some wrong keys

Just a rough approximation would be

5 + 8 + 13 = 26, not 6.06!

- Algebra -
**Student**, Tuesday, March 11, 2014 at 12:34pmWell, I entered in the calculator √28 + √63 + √175 and got 6.06. I just entered the expression. I didn't take the sq roots first.

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