if venom A is three times as potent as venom B and venom C is 2.2 times as potent as venom B. how much more potent is venom C compared to venom A?
vA = 3 x vB
vC = 2.2 x vB
vC : vA
(2.2vB):(3vB)
11:15
vC is 0.733 times more potent than vA
To find out how much more potent venom C is compared to venom A, we need to compare their potencies.
Given that venom A is three times as potent as venom B, and venom C is 2.2 times as potent as venom B, we can determine the relative potencies of venom A, B, and C.
Let's assume that the potency of venom B is "x".
Since venom A is three times as potent as venom B, we can represent the potency of venom A as 3x.
Similarly, venom C is 2.2 times as potent as venom B, so its potency can be represented as 2.2x.
To find out how much more potent venom C is compared to venom A, we subtract the potency of venom A from that of venom C:
Potency of Venom C - Potency of Venom A
= 2.2x - 3x
Simplifying this equation, we get:
= -0.8x
Since the result is negative, we can conclude that venom C is 0.8 times (or 80%) less potent than venom A.