please,please help!im doing subtraction with renaming but don't understand.I have to estimate,then find the difference and write in simplest form.I just need help with two and may be able to do the rest on my own.6 and 1/3 minus 3 and 5/6 is the first one and 9 minus 3 and 7/8 is the second one?

Question

please,please help!im doing subtraction with renaming but don't understand.I have to estimate,then find the difference and write in simplest form.I just need help with two and may be able to do the rest on my own.6 and 1/3 minus 3 and 5/6 is the first one and 9 minus 3 and 7/8 is the second one?

Answer 1

rename 6 1/3 to 5 4/3

now subtract 3 5/6

opps, rename first to 5 8/6, now subtract

2 3/6 or 2 1/2

Answer 2

Don't understand mr.bobpursley,someone please help me break this down

Answer 3

5 8/6 - 3 5/6 = 2 3/6 = 2 1/2

Answer 4

first im sorry I wrote the problem wrong and the problem is 4 1/2 minus 3 5/6 and my second problem is 9 minus 3 7/8?i don't understand even with the problem they showed which is..6 1/3 minus 1 2/5,that ended up being 6 5/15 minus 1 6/15,they crossed out the first 6 and made it a 5 and the 5 that's over the 15 they crossed it out and put 20 over it,sounds confusing?

Answer 5

This video may help you.

http://www.youtube.com/watch?v=anyY8lGamJI

Answer 6

Of course, I'd be happy to help you with subtraction involving renaming. Let's start with the first problem: 6 and 1/3 minus 3 and 5/6.

To subtract these mixed numbers, we need to rename the fractions so that they have common denominators. Let's find a common denominator before we subtract:

The fractions involved are 1/3 and 5/6. The least common multiple (LCM) of 3 and 6 is 6. So, we'll rename 1/3 as 2/6, since multiplying the numerator and denominator of 1/3 by 2 gives us 2/6.

Now, we can subtract:
6 and 1/3 - 3 and 5/6
= 6 - 3 + 2/6 - 5/6
= 3 + (2/6 - 5/6)

The denominators are now the same, so we can subtract the numerators:
= 3 + (-3/6)
= 3 - 1/2
= 2 and 1/2

So, the difference is 2 and 1/2. Now let's move on to the second problem: 9 - 3 and 7/8.

We can start by subtracting the whole numbers, just like in regular subtraction:
9 - 3 = 6

Now we need to subtract the fraction, which is 7/8. However, 7/8 is larger than 6/8. To handle this, we'll need to borrow from the whole number.

We can borrow 1 from the 9, and that leaves us with 8. So, the problem becomes:
8 + 6/8 - 7/8

Now, we can subtract the fractions:
= 8 + (6/8 - 7/8)
= 8 - 1/8
= 7 and 7/8

Therefore, the difference is 7 and 7/8.

I hope that helps! If you have any further questions, feel free to ask.