The pressure on a gas at -58 degrees Celcius is doubled, but its volume is held constant. What will the final temperature be in degrees Celsius?

PV/T is constant

So, if we have 2P, we need
2T to hold the ratio. (T, of course is Kelvin)

78

To determine the final temperature of the gas, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature when pressure is held constant.

In this scenario, the volume is held constant, so we can use this formula:

(V1 / T1) = (V2 / T2)

where:
V1 = initial volume
T1 = initial temperature
V2 = final volume
T2 = final temperature

Since the volume is constant, V1 = V2. Thus, the equation becomes:

V1 / T1 = V1 / T2

Now we can solve for T2, the final temperature.

Given:
T1 = -58 degrees Celsius (initial temperature)
V1 = V2 (constant volume)

Let's denote the final temperature as T2.

V1 / T1 = V1 / T2

Since V1 and V2 are equal, we cancel them out:

1 / T1 = 1 / T2

To solve for T2, we can cross-multiply:

T2 = T1

Therefore, the final temperature will be -58 degrees Celsius, the same as the initial temperature.