A Department of Transportation report about air travel that 5 out of every 1000 pieces of luggage are lost by the airlines. You are traveling with a group of people who have 22 pieces of luggage. What is the probability that 2 of these are lost? Set up the equation and plug in all the numbers.
prob(lost) = 5/1000 = 1/200
prob(not lost) = 199/200
prob( 2 of 22 are lost)
= C(22,2) (1/200)^2 (199/200)^20
= .005224..
Question for you.
would this be the same as
"....a group of people who have 11 pieces of luggage. What is the probability that 1 of these are lost? "