You have a total of $175 in $5 and $20 bills. The number of $5 bills you have is 3 more than 4 times the number of $20 bills. How many of each type of bill do you have?
5x+20y = 175
x = 4y+3
Now just solve for x and y
i need the answer
To solve this problem, we can set up a system of equations to represent the given information.
Let's denote the number of $5 bills as "x" and the number of $20 bills as "y."
The problem states that the total amount of money in $5 and $20 bills is $175. Since each $5 bill has a value of $5 and each $20 bill has a value of $20, we can express this information in equation form as:
5x + 20y = 175 Equation 1
The problem also states that the number of $5 bills is 3 more than 4 times the number of $20 bills. Mathematically, we can express this relationship as:
x = 4y + 3 Equation 2
Now, we have a system of equations. We can solve them simultaneously to find the values of x and y.
Substitute the expression for "x" from Equation 2 into Equation 1:
5(4y + 3) + 20y = 175
20y + 15 + 20y = 175
40y + 15 = 175
40y = 160
y = 4
Now, substitute the value of "y" back into Equation 2 to find "x":
x = 4y + 3
x = 4(4) + 3
x = 16 + 3
x = 19
Therefore, there are 19 $5 bills and 4 $20 bills.