A woman drove a distance of 100km/h, on the journey she drove 10km/h faster and took 30min less. What was her speed on the outward journey?

since time distance/speed,

100/s = 100/(s+10) + 1/2
s = 40

What if she was rolling, anthony?

Steve, i'm still trying to use you way...

Steve, can you explain a bit furthur, please???

compare the times.

The time it took to cover 100km at speed s is 100/s

That was 1/2 hour more than the time it took to cover 100km at the faster speed, s+10

Mr. tan makes monthly visits to his parents in Malacca a distance of 240 km from Singapore. he finds that if he increases the average speed by 10km/h, he could save a total of 20min for the journey. find the original speed of Mr. tan.

To find the woman's speed on the outward journey, we can use the formula for speed, which is distance divided by time. Let's assume her speed on the outward journey is x km/h.

On the return journey, she drove 10 km/h faster, so her speed would be (x + 10) km/h.

We also know that the journey took 30 minutes less on the return journey. We need to convert this time to hours, so we divide 30 minutes by 60 to get 0.5 hours.

Now let's calculate the time for each journey. On the outward journey, the time can be calculated as distance divided by speed:

Time for outward journey = 100 km / x km/h

And on the return journey, the time is:

Time for return journey = 100 km / (x + 10) km/h

According to the problem, the return journey took 30 minutes less. So we can write the equation:

Time for outward journey - Time for return journey = 0.5 hours

Substituting the equations we calculated earlier:

100 km / x km/h - 100 km / (x + 10) km/h = 0.5 hours

Now we can solve this equation to find the value of x, representing her speed on the outward journey.