Find the real and imaginary zeros for the following polynomial function.
T(b)= 147b^3-35b^2-19b+3
147b^3-35b^2-19b+3 = 0
Since 147 = 7*7*3, I'd try using those coefficients first, since the inside coefficients are relatively small. A little playing around shows that
T(b) = (7b-1)(7b-3)(3b+1)