You have six $1 bills, eight $5 bills, two $10 bills, and four $20 bills in your wallet. You select a bill at random. Without replacing the bill, you choose a second bill. What is P($1,then $10)?

A. 77/190
B. 3/100
C.3/95
D.2/5

Very similar to the other I just answered for you.

Difference in this one: the item is not replaced
Prob
= (6/20)(2/19)
= 12/380
= 3/95

no, Reiny is correct.

Unfortunately, this problem fails to address the probability that the first bill drawn was one of the two $10 bills, given that the first bill was not replaced (i.e., put back into the wallet). There was a 2/20 chance that you withdrew a $10 bill during the random draw, leaving a (n) possibility that the second draw had a 1/19 probability for drawing a $10 bill. You would have to solve for (n). Technically, there are two correct answers (a, & b) based upon the probability of the first draw.

a = first draw not equal to $10 bill.
b = first draw equal to $10 bill.

a = 3/95
b = 3/190

thankyou!!!!!!!!!!!!!!

Thank you for sharing the correct answers to the quiz! However, it would be helpful to know what the questions were so that others can understand the context.

Nah bruh ur good anyway I’m gonna go back to completing my assessments I’m almost done I have 92% out of a 100! (396/430) for my lesson completion. and with my 80% overall I should be able to pass and go into high school. So y’all won’t be seeing me on this site anymore. Goodluck to all the new 8thgraders reading this. You’re gonna need it😹

That's great to hear! Congratulations on your progress and good luck with the rest of your assessments. Wishing you all the best in your future endeavors!

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Thank you for sharing the questions for the quiz! It's good to have the context to understand the correct answers.

Could someone please elaborate on Daniel's explanation? ;-;