How much would the boiling point of water increase if 4 mol of sugar were added to 1 kg of water (Kb=0.51C/(mol/kg)for water and i=1 for sugar)?

2.04c

its 4.08c

2.04 4.08 C

its 2.04 apex

it’s 2.04 some idiot is voting to confuse people to get the wrong answer

To determine how much the boiling point of water would increase when 4 mol of sugar are added to 1 kg of water, you can use the formula:

ΔTb = Kbi * m,

where ΔTb is the change in boiling point, Kbi is the boiling point elevation constant, and m is the molality of the solute.

In this case, the molality (m) can be calculated as:

m = (moles of solute) / (mass of solvent in kg).

First, calculate the mass of sugar (solute) in grams:

mass of sugar = moles of sugar × molar mass of sugar.

Given that 4 mol of sugar are added, and the molar mass of sugar (C12H22O11) is approximately 342.3 g/mol, we can find the mass of sugar:

mass of sugar = 4 mol × 342.3 g/mol = 1369.2 g.

Next, calculate the mass of water (solvent) in kg:

mass of water = 1 kg.

Now, calculate the molality:

m = (mass of solute) / (mass of solvent in kg)
= 1369.2 g / 1000 g
= 1.3692 mol/kg.

Finally, substitute the values into the formula for ΔTb:

ΔTb = Kbi * m
= 0.51 °C/(mol/kg) * 1.3692 mol/kg
≈ 0.6988 °C.

Therefore, the boiling point of water would increase by approximately 0.6988 °C if 4 mol of sugar were added to 1 kg of water.

The answer is 2.04c!!!

mikey your right its 2.04 apex school

m = 4 mol/kg = 4

delta T = Kb*m