20.00 mL of a H2SO4 solution with an unknown concentration was titrated to a phenolphthalein endpoint with 39.13 mL of a 0.1061 M NaOH solution. What is the concentration of the H2SO4 solution?

To find the concentration of the H2SO4 solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between H2SO4 and NaOH.

The balanced equation for the reaction is:
H2SO4 + 2NaOH -> Na2SO4 + 2H2O

From the balanced equation, we can see that the molar ratio between H2SO4 and NaOH is 1:2. This means that for every 1 mole of H2SO4, 2 moles of NaOH are required to react completely.

First, let's calculate the number of moles of NaOH used in the titration:

Moles of NaOH = Volume of NaOH solution (in liters) x Concentration of NaOH solution (in moles/liter)
= 39.13 mL x (1 L / 1000 mL) x 0.1061 M

Now, we can use the mole ratio to determine the number of moles of H2SO4 present in the titration:

Moles of H2SO4 = (1/2) x Moles of NaOH

We know that the volume of the H2SO4 solution used in the titration is 20.00 mL (which is equivalent to 0.02000 liters).

Finally, we can use the calculated moles of H2SO4 and the volume of the H2SO4 solution to find its concentration:

Concentration of H2SO4 = Moles of H2SO4 / Volume of H2SO4 solution (in liters)

Now we can put these values into the equations to find the concentration of the H2SO4 solution.

Moles of NaOH = 39.13 mL x (1 L / 1000 mL) x 0.1061 M
= 0.004150 moles

Moles of H2SO4 = (1/2) x 0.004150 moles
= 0.002075 moles

Concentration of H2SO4 = 0.002075 moles / 0.02000 L
= 0.1038 M

Therefore, the concentration of the H2SO4 solution is 0.1038 M.

To find the concentration of the H2SO4 solution, we can use the equation:

M1V1 = M2V2

Where:
M1 = concentration of H2SO4 solution
V1 = volume of H2SO4 solution
M2 = concentration of NaOH solution
V2 = volume of NaOH solution

Given the following values:
V1 = 20.00 mL
M2 = 0.1061 M
V2 = 39.13 mL

Substituting these values into the equation, we have:

M1 * 20.00 mL = 0.1061 M * 39.13 mL

Now, we can solve for M1 (concentration of H2SO4 solution):

M1 = (0.1061 M * 39.13 mL) / 20.00 mL

M1 = 0.207 M

Therefore, the concentration of the H2SO4 solution is 0.207 M.

volumeacid*Normality acid=volumebase*normality base

20.00*Mconc*2 = 39.13*.1061
solve for Mconce, the molarity of the H2SO4