On joes farm there are 99 animals. There are four times as many cows as horses on the farm. There are twice as many horses as lives. How many horses, cows, and pigs are there?

c+h+p = 99

c = 4h
h = 2p

4(2p) + 2p + p = 99
11p = 99
p = 9
so, 18 horses, 72 cows, 9 pigs

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To find out how many horses, cows, and pigs are on Joe's farm, we can break down the information provided step by step.

Let's start with the fact that there are 99 animals in total on the farm.

Next, it says there are four times as many cows as horses. Let's assume the number of horses is H. Therefore, the number of cows would be 4H.

We also know that there are twice as many horses as pigs. So, the number of horses would be 2P.

Since we are looking for the number of horses, cows, and pigs, we need to assign variables to each of them.

Let's say:
H = number of horses
C = number of cows
P = number of pigs

Now, let's use the information given to form equations:

Equation 1: H + C + P = 99 (total number of animals on the farm)
Equation 2: C = 4H (four times as many cows as horses)
Equation 3: H = 2P (twice as many horses as pigs)

Now, we can solve this system of equations to find the values of H, C, and P.

Substituting Equation 2 and Equation 3 into Equation 1, we have:
(4H) + H + (H/2) = 99

Combining like terms:
8H/2 + 2H/2 + H/2 = 99
(8H + 2H + H)/2 = 99
11H/2 = 99

To isolate H, we multiply both sides of the equation by 2:
11H = 99 * 2
11H = 198
H = 198/11
H = 18

Now, we can substitute this value back into equations 2 and 3 to find the values of C and P.

Using Equation 2:
C = 4H
C = 4 * 18
C = 72

Using Equation 3:
P = H/2
P = 18/2
P = 9

Thus, there are 18 horses, 72 cows, and 9 pigs on Joe's farm.