what is the net ionic equation for the following molecular equation. HNO3 is strong electrolyte and CH3COOH is weak electrolyte. NaCH3COO(aq)+HNO3(aq)----->NaNO3(aq)+CHOOH(aq)
the same question says use H+ for the hydronium ion, CH3OOH for acetic acid and CH3COO for the acetate ion.
The answer should be like as below:
answer + answer---> answer + answer
it has four boxes, pretend the answer is one box. i hope this helps
To write the net ionic equation for the given molecular equation, we need to first write the dissociation equations for the strong electrolyte (HNO3) and the weak electrolyte (CH3COOH).
HNO3 (aq) → H+ (aq) + NO3- (aq)
CH3COOH (aq) ⇌ CH3COO- (aq) + H+ (aq)
Now, we can rewrite the chemical equation using the dissociated forms:
Na+ (aq) + CH3COO- (aq) + H+ (aq) + NO3- (aq) → Na+ (aq) + NO3- (aq) + CH3COOH (aq)
Since Na+ and NO3- are spectator ions (they do not participate in the reaction), we can remove them from the equation to get the net ionic equation:
CH3COO- (aq) + H+ (aq) → CH3COOH (aq)
So, the net ionic equation for the given molecular equation is:
CH3COO- (aq) + H+ (aq) → CH3COOH (aq)