magnesium chlorate under goes decompostion, oxgen gas is realsed in the following reaction:
2KClO3 → 2KCl + 3O2
when 3.50 grams of potassuim chlorate is decomposed at STP, how many litters of oxgen will be produced?
Two errors to point out. You say magnesium chlorate but use potassium chlorate. Second, L is liters, not litters (as in a litter of puppies).
Convert grams KClO3 to mols. mols = grams/molar mass
Using the coefficients in the balanced equation, convert mols KClO3 to mols O2.
Then convert mols O2 to L. 22.4 L/mol x mols = ?L
It will be 22.4 x 3/2 x the moles of KClO3
moles KClO3= 3grams/molmasspotassiumchlorate
To find the number of liters of oxygen gas produced when 3.50 grams of potassium chlorate (KClO3) is decomposed at standard temperature and pressure (STP), you will need to use the given balanced chemical equation:
2KClO3 → 2KCl + 3O2
First, calculate the number of moles of potassium chlorate using its molar mass. The molar mass of KClO3 is calculated by adding the atomic masses of potassium (K), chlorine (Cl), and oxygen (O).
Molar mass of KClO3 = (1 × atomic mass of K) + (1 × atomic mass of Cl) + (3 × atomic mass of O)
= (1 × 39.10 g/mol) + (1 × 35.45 g/mol) + (3 × 16.00 g/mol)
= 122.55 g/mol
Now, calculate the number of moles of potassium chlorate:
Number of moles = Mass / Molar mass
Number of moles = 3.50 g / 122.55 g/mol
Next, use the stoichiometric ratio between potassium chlorate (KClO3) and oxygen (O2) to determine the number of moles of oxygen gas produced. From the balanced chemical equation, you can see that 2 moles of potassium chlorate react to produce 3 moles of oxygen.
By comparing the coefficients, you can see that:
2 moles of KClO3 react to produce 3 moles of O2
Therefore, if x moles of KClO3 decompose, then:
(3 moles of O2 / 2 moles of KClO3) = (x moles of O2 / 3.50 moles of KClO3)
Now, solve for x:
x = (3 moles of O2 / 2 moles of KClO3) * (3.50 moles of KClO3)
Finally, convert the number of moles of oxygen gas (x) to liters using the ideal gas law at STP:
1 mole of any ideal gas occupies 22.4 liters at STP.
Therefore, the number of liters of oxygen gas produced will be:
Liters of O2 gas = x moles of O2 * 22.4 liters/mole
Plug in the value of x to get the final result.
Note: Since you did not provide the value of x (moles of O2), you will need to calculate it using the equation above before finding the final answer.