2r(r - 3) + 4(3 - r) , ahhh, did you notice that the brackets are opposite? , so ..
= 2r(r-3) - 4(r - 3)
Use the same "trick" on the others if you have to.
My textbook says the answer is 2(r-2)(r-3), though.
Surely you could see that 2 was an additional common factor contained in my (2r-4) factor.
What? I don't understand what you mean.
look at my answer ...
My answers to the other equations:
3. (w^2 + 1)(w - 4)
4. (2p^2 - 5)(p - 3)
2. (7q - 2)(2q - 3).
3 and 4 are correct
14q^2 - 21q + 6 - 4q
= 7q(2q - 3) + 2(3-2q)
= 7q(2q-3) - 2(2q-3)
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